matchingR
is an R package which quickly computes the Gale-Shapley algorithm
(Gale and Shapley 1962), Irving’s
algorithm for the stable roommate problem (Irving 1985), and the top
trading cycle algorithm (Shapley and Scarf
1973) for large matching markets. The package provides functions
to compute the solutions to the stable marriage
problem, the college admission
problem, the stable
roommates problem, and the house
allocation problem.
The package may be useful when the number of market participants is large or when many matchings need to be computed (e.g., for simulation or estimation purposes). It has been used in practice to compute the Gale-Shapley stable matching with 30,000 participants on each side of the market.
Matching markets are common in practice and widely studied by economists. Popular examples include
Consider the following marriage market: There are N
men
and N
women. Each man, m
, receives utility
uM(w, m)
from a match with woman w
, and
similarly each woman receives a payoff of uW(m, w)
from
being matched with a man.
A matching assigns men to women such that each man is assigned to one
woman and each woman is assigned to one man. A matching is
stable if there is no man and woman who would jointly
prefer to be matched to each other over their current spouses. In other
words, a matching is stable if there are no pairs
(m, w'), (m', w)
, such that m
is matched with
w'
, m'
is matched with w
, and
both uW(m, w) > uW(m', w)
and
uM(m, w) > uM(m, w')
.
For example, we might have preferences for men given by
## cols
## rows Man 1 Man 2 Man 3
## Woman 1 1.0 0.5 0.0
## Woman 2 0.5 0.0 0.5
## Woman 3 0.0 1.0 1.0
In this example, man 1
receives a payoff of
1.0
from being matched to woman 1
, a payoff of
0.5
from being matched to woman 2
and a payoff
of 0.0
from being matched to woman 3 (same logic applies to
men 2
and 3
). Similarly, we might have
preferences for women given by
## cols
## rows Woman 1 Woman 2 Woman 3
## Man 1 0.0 1.0 0.0
## Man 2 0.5 0.0 0.5
## Man 3 1.0 0.5 1.0
Here, columns in the matrix correspond to women, rows to men. In this
example, woman 1
receives a payoff of 0.0
from
being matched to man 1
, a payoff of 0.5
from
being matched to man 2
and a payoff of 1.0
from being matched to man 3 (same logic applies to women 2
and 3
).
Instead of using payoff matrices, we can also represent preferences
using preference orderings. The preference ordering that corresponds to
uM
is
## cols
## rows Man 1 Man 2 Man 3
## Rank 1 1 3 3
## Rank 2 2 1 2
## Rank 3 3 2 1
prefM
states that man 1
prefers woman
1
over woman 2
over woman 3
, etc.
The preference ordering that corresponds to uW
is given
by
## cols
## rows Woman 1 Woman 2 Woman 3
## Rank 1 3 1 3
## Rank 2 2 3 2
## Rank 3 1 2 1
The matching algorithm discussed below can take either payoff
matrices of the type uM
and uW
or preference
orderings of the type prefM
and prefW
as
arguments.
The Gale-Shapley algorithm works as follows: Single men (“the proposers”) sequentially make proposals to each of their most preferred available women (“the reviewers”). A woman can hold on to at most one proposal at a time. A single woman will accept any proposal that is made to her. A woman who already has a proposal will reject any proposal she values less than her current proposal in hand. If a woman receives a proposal from a man that she values more than her current proposal, she will accept the proposal and her previous match will rejoin the line of proposers. This process continues until all men are matched to all women.
For the preferences specified in uM
and uW
,
we can compute the Gale-Shapley Algorithm by hand. Initially, all men
are single.
1
proposes to woman 1
, his
most-preferred choice.2
, 3
2
proposes to woman 3
, his
most-preferred choice.3
3
proposes to woman 3
, his
most-preferred choice.3
now dumps man 2
.2
2
proposes to woman 1
, his
most-preferred available choice.1
now dumps man 1
.1
1
proposes to woman 2
, his
most-preferred available choice.The man-optimal stable matching is therefore:
Man | Woman |
---|---|
1 | 2 |
2 | 1 |
3 | 3 |
The package computes the Gale-Shapley algorithm using the function
galeShapley.marriageMarket
:
Note that we can obtain equivalent results when we use
prefM
and prefW
as arguments:
The function galeShapley.marriageMarket
returns a list
matching
that includes the vectors proposals
and engagements
with the final proposals and engagements,
respectively. These two vectors contain the same information (i.e. they
tell us who is matched with whom). For the example above, the vector of
proposals contains
## cols
## rows Proposed to Woman
## Man 1 2
## Man 2 1
## Man 3 3
The first element in the vector tells us that man 1
is
matched with woman 2
. Man 2
is matched to
woman 1
, and man 3
is matched to woman
3
. The vector of engagement contains
## cols
## rows Engaged to Man
## Woman 1 2
## Woman 2 1
## Woman 3 3
The first element in the vector tells us that woman 1
is
matched to man 2
, woman 2
will be matched to
man 1
, and woman 3
will be matched to man
3
.
We can then check if the computed matching is stable using the
function checkStability
. To check if a matching is stable,
we check for each assignment (m,w)
if there is some other
woman w'
that man m
would rather be matched
with and who would rather be matched to man m
. This
function will return true
if the matching is stable and
false
otherwise.
## [1] TRUE
For the simple 3-by-3 example, we can perform this check by hand:
1
is matched to woman 2
, his
second-most preferred choice. His most preferred choice is woman
1
. Woman 1
is matched with man 2
who she prefers over man 1
. Thus man 1
cannot
do better than woman 2
.2
is matched to woman 1
, his
second-most preferred choice. His most preferred woman is woman
3
, who is matched with man 3
. Since man
3
is her most-preferred choice, man 2
cannot
do better than woman 1
.3
is matched to women 3
, his most
preferred choice, so he cannot do better.Thus, this matching is stable.
The following examples illustrate some additional features of this package.
The following is an example of
galeShapley.marriageMarket
with different numbers of
participants on each side of the market. There are 2,500 women and 2,000
men. By construction, 500 men will remain unmatched. We randomly
generate payoff matrices uM
and uW
which are
drawn from a uniform distribution (runif
). We then compute
the male-optimal (i.e. men are proposing) and the female-optimal
(i.e. woman are proposing) matching.
# set seed
set.seed(1)
# set number of men
nmen = 2500
# set number of women
nwomen = 2000
# generate preferences
uM = matrix(runif(nmen*nwomen), nrow = nwomen, ncol = nmen)
uW = matrix(runif(nmen*nwomen), nrow = nmen, ncol = nwomen)
# male-optimal matching
resultsM = galeShapley.marriageMarket(uM, uW)
str(resultsM)
## List of 4
## $ proposals : num [1:2500, 1] 927 1644 1965 1851 349 ...
## $ engagements : num [1:2000, 1] 386 471 1582 598 1657 ...
## $ single.proposers: num [1:500] 8 11 17 19 26 30 34 37 49 53 ...
## $ single.reviewers: num(0)
## [1] TRUE
## List of 4
## $ proposals : num [1:2000, 1] 386 471 1582 598 1657 ...
## $ engagements : num [1:2500, 1] 927 1644 1965 1851 349 ...
## $ single.proposers: num(0)
## $ single.reviewers: num [1:500] 8 11 17 19 26 30 34 37 49 53 ...
## [1] TRUE
The following is an example of
galeShapley.collegeAdmissions
where 1000 students get
matched to 400 colleges, where each college has two slots. By
construction, 200 students will remain unmatched. We draw students’ and
colleges’ preferences, uStudents
and
uColleges
, respectively, by from a uniform
distribution.
# set seed
set.seed(1)
# set number of students
nstudents = 1000
# set number of colleges
ncolleges = 400
# generate preferences
uStudents = matrix(runif(ncolleges*nstudents), nrow = ncolleges, ncol = nstudents)
uColleges = matrix(runif(nstudents*ncolleges), nrow = nstudents, ncol = ncolleges)
# student-optimal matching
results = galeShapley.collegeAdmissions(studentUtils = uStudents, collegeUtils = uColleges, slots = 2)
str(results)
## List of 4
## $ unmatched.students: num [1:200] 3 15 23 29 30 36 44 46 48 49 ...
## $ unmatched.colleges: int(0)
## $ matched.colleges : num [1:400, 1:2] 728 887 28 372 875 775 456 937 402 774 ...
## $ matched.students : int [1:1000, 1] 52 70 NA 210 155 170 238 16 371 391 ...
# check if matching is stable
galeShapley.checkStability(uStudents, uColleges, results$matched.students, results$matched.colleges)
## [1] TRUE
This package implements the algorithm by Irving (1985) for one-sided matching markets.
Consider the following example: A set of n
potential
roommates, each with ranked preferences over all the other potential
roommates, are to be matched to rooms, two roommates per room. A
matching is stable if there is no roommate
r1
that would rather be matched to some other roommate
d2
than to his current roommate r2
and the
other roommate d2
would rather be matched to
r1
than to his current roommate d1
.
Preferences of potential roommates are summarized by an n − 1 × n dimensional matrix, e.g., if n = 6,
pref = matrix(c(3, 6, 2, 5, 3, 5,
4, 5, 4, 2, 1, 1,
2, 4, 5, 3, 2, 3,
6, 1, 1, 6, 4, 4,
5, 3, 6, 1, 6, 2), nrow = 5, ncol = 6, byrow = TRUE)
Column i
represents the preferences of the
i
th roommate, and row j
represents the ranking
of the roommate whose index is encoded in that row. For example, in the
above preference matrix, roommate 1
most prefers to be
matched with roommate 3
, followed by 4
,
followed by 2
.
The function roommate.checkPreferences
checks if a given
preference order is complete, i.e. if all preferences are fully
specified. If the preference order is complete, it will return the
proper preference order using C++
style indexing (beginning
at 0
instead of at 1
). If the preference order
is incomplete, the function will return an error.
## [,1] [,2] [,3] [,4] [,5] [,6]
## [1,] 2 5 1 4 2 4
## [2,] 3 4 3 1 0 0
## [3,] 1 3 4 2 1 2
## [4,] 5 0 0 5 3 3
## [5,] 4 2 5 0 5 1
The algorithm proceeds in two phases.
In phase 1, potential roommates take turns sequentially proposing to the other roommates. Each roommate who is proposed to can accept or reject the proposal. A roommate accepts if he currently has made no better proposal which was accepted to another roommate. If a roommate has accepted a proposal, and then receives a better proposal, he rejects the old proposal and substitutes in the new proposal.
In the above example,
1
begins by proposing to roommate
3
, his most preferred roommate. 3
, having no
better offers, accepts.2
proposes to 6
, who accepts.3
proposes to 2
, who accepts.4
proposes to 5
, who accepts.5
proposes to 3
, who accepts.
3
cancels his proposal from 1
.1
, having no proposal, proposes to 4
, who
accepts.6
proposes to 5
, who rejects, having a
better proposal from 4
.6
proposes to 1
, who accepts.In phase 2, we begin by eliminating all potential roommate matches
which are worse than the current proposals held. For example, in the
above example, 3
has a proposal from 5
, and so
we eliminate 1
and 6
from 3
‘s
column, and symmetrically eliminate 3
from 1
and 6
’s column. This results in the following ’reduced’
preference listing:
6, 2, 5, 3,
4, 5, 4, 2, 1
2, 4, 5, 3, 2,
6, 1, 6, 4, 4
3, 1, 2
These preferences form what is called a ‘stable’ table, or,
‘s-table’. (‘Stable’ for short.) The defining characteristic of a stable
table is that if i
is the most preferred roommate on
j
s list, then j
is the least preferred
roommate on i
s list. For example, 1
most
prefers 4
, but 4
least prefers
1
.
The algorithm proceeds by finding and eliminating ‘rotations’. A rotation is a sequence of pairs of roommates, such that there is a distinct roommate in the first position of each pair, the second roommate in each pair least prefers the roommate he is paired with, the first roommate in each pair most prefers the roommate he is paired with, and finally, the first roommate in each pair ranks the second roommate in the following pair second (modulo the number of pairs, that is, the first roommate in the last pair ranks the second roommate in the first pair second) Once a rotation has been identified, removing it results in another stable table.
For example, (1, 4), (3, 2)
is a rotation in the above
table, because 1
loves 4
, 3
loves
2
, 4
hates 1
, 2
hates 3
, 2
is second on 1
s list,
and 4
is second on 3
’s list. Eliminating this
rotation involves 2
rejecting 3
,
4
rejecting 1
, and then we remove every
successive potential roommate as well to preserve the stable table
property, resulting in
6, 5, 3,
5, 4, 2, 1
2, 4, 5, 3, 2,
6, 1, 6, 4, 4
2
A further rotation is (1, 2), (2, 6), (4, 5)
.
Eliminating it yields
3,
5, 4, 2, 1
4, 5, 3, 2,
6,
A final rotation is (2, 5), (3, 4)
. Eliminating it
yields
3,
2, 1
4, 5,
6,
Therefore, a stable matching is for 1
and 6
to match, 2
and 4
to match, and 3
and 5
to match.
## [,1]
## [1,] 6
## [2,] 4
## [3,] 5
## [4,] 2
## [5,] 3
## [6,] 1
The function roommate.checkStability
can be used to
check if the resulting matching is stable:
## [1] TRUE
The function roommate
can also be called using a payoff
matrix, u
, to specify preferences. In u
, the
element [i,j]
refers to the payoff that agent
j
gets from being matched to agent i
. The main
diagonal of this matrix contains no information and will be removed by
the algorithm.
# generate preferences
N = 10
u = matrix(runif(N^2), nrow = N, ncol = N)
results = roommate(utils = u)
results
## [,1]
## [1,] 3
## [2,] 4
## [3,] 1
## [4,] 2
## [5,] 7
## [6,] 10
## [7,] 5
## [8,] 9
## [9,] 8
## [10,] 6
## [1] TRUE
Note that in the roommate problem, existence of a stable matching is
not guaranteed. When no stable matching can be found, the function
roommate
returns NULL
.
set.seed(1)
N = 512
u = matrix(runif(N^2), nrow = N, ncol = N)
results = roommate(utils = u)
print(results)
## NULL
This package implements the top trading cycle algorithm.
Consider the following problem: A set of n agents each currently own their own home, and have preferences over the homes of other agents. The problem is to trade the homes between the agents in such a way so that no two agents want to swap homes.
Preferences of agents are summarized by an n × n dimensional matrix, e.g., if n = 4,
Column i represents the
preferences of the ith agent,
and row j represents the
ranking of the roommate whose index is encoded in that row. For example,
in the above preference matrix, agent 1
most prefers the
home of agent 4
, followed by 2
, followed by
1
, followed by 3
.
Roughly speaking, the top trading cycle proceeds by identifying cycles of agents, then eliminating those cycles until no agents remain. A cycle is a sequence of agents such that each agent most prefers the next agent’s home (out of the remaining unmatched agents), and the last agent in the sequence most prefers the first agent in the sequence’s home.
4, 4, 2, 4
2, 1, 1, 1
1, 2, 3, 3
3, 3, 4, 2
For example, for the above preference matrix, when all the agents are
unmatched, the only rotation is {4},
representing the fact that agent 4
most prefers his own
house. Therefore, the algorithm begins by matching agent 4
to himself, and then removing him from the pool:
2
2, 1, 1
1, 2, 3
3, 3,
Now, a rotation is {1, 2}, because
1
most prefers 2
s house, and 2
most prefers 1
s house. So agents 1
and
2
will swap homes, leaving agent 3
all by
himself.
3
Therefore, the final matching is that agent 1
swaps with
agent 2
, and agents 3
and 4
keep
their own homes.
## [,1]
## [1,] 2
## [2,] 1
## [3,] 3
## [4,] 4
The function toptrading.checkStability
can be used to
check if the resulting allocation is in fact stable:
## [1] TRUE